Java.util.Arrays.sort(double[]) Method

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Description

The java.util.Arrays.sort(double[]) method sorts the specified array of doubles into ascending numerical order.

Declaration

Following is the declaration for java.util.Arrays.sort() method

public static void sort(double[] a)

Parameters

  • a -- This is the array to be sorted.

Return Value

This method does not return any value.

Exception

  • NA

Example

The following example shows the usage of java.util.Arrays.sort() method.

package com.tutorialspoint;

import java.util.Arrays;

public class ArrayDemo {

   public static void main(String[] args) {

    // initializing unsorted double array
    double dArr[] = {3.2, 1.2, 9.7, 6.2, 4.5};

    // let us print all the elements available in list
    for (double number : dArr) {
      System.out.println("Number = " + number);
    }

    // sorting array
    Arrays.sort(dArr);

    // let us print all the elements available in list
    System.out.println("The sorted double array is:");
    for (double number : dArr) {
      System.out.println("Number = " + number);
    }
  }
}

Let us compile and run the above program, this will produce the following result:

Number = 3.2
Number = 1.2
Number = 9.7
Number = 6.2
Number = 4.5
The sorted double array is:
Number = 1.2
Number = 3.2
Number = 4.5
Number = 6.2
Number = 9.7



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