Java.util.Arrays.binarySearch() Method

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Description

The java.util.Arrays.binarySearch(long[] a, long key) method searches the specified array of longs for the specified value using the binary search algorithm.The array must be sorted before making this call.If it is not sorted, the results are undefined.

Declaration

Following is the declaration for java.util.Arrays.binarySearch() method

public static int binarySearch(long[] a, long key)

Parameters

  • a -- This is the array to be searched.

  • key -- This is the value to be searched for.

Return Value

This method returns index of the search key, if it is contained in the array, else it returns (-(insertion point) - 1). The insertion point is the point at which the key would be inserted into the array: the index of the first element greater than the key, or a.length if all elements in the array are less than the specified key.

Exception

  • NA

Example

The following example shows the usage of java.util.Arrays.binarySearch() method.

package com.tutorialspoint;

import java.util.Arrays;

public class ArrayDemo {

   public static void main(String[] args) {

    // initializing unsorted long array
    long longArr[] = {56,46464,3342,232,3445};

    // sorting array
    Arrays.sort(longArr);

    // let us print all the elements available in list
    System.out.println("The sorted long array is:");
    for (long number : longArr) {
      System.out.println("Number = " + number);
    }

    // entering the value to be searched
    long searchVal = 232;

    int retVal = Arrays.binarySearch(longArr,searchVal);

    System.out.println("The index of element 232 is : " + retVal);
  }
}

Let us compile and run the above program, this will produce the following result:

The sorted long array is:
Number = 56
Number = 232
Number = 3342
Number = 3445
Number = 46464
The index of element 232 is : 1



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