Java.math.BigInteger.shiftRight() Method



The java.math.BigInteger.shiftRight(int n) returns a BigInteger whose value is (this >> n). Sign extension is performed. The shift distance, n, may be negative, in which case this method performs a left shift. It computes floor(this / 2n).


Following is the declaration for java.math.BigInteger.shiftRight() method

public BigInteger shiftRight(int n)


  • n - shift distance, in bits

Return Value

This method returns a BigInteger object whose value is this >> n .


  • ArithmeticException - if the shift distance is Integer.MIN_VALUE


The following example shows the usage of math.BigInteger.shiftRight() method

package com.tutorialspoint;

import java.math.*;

public class BigIntegerDemo {

public static void main(String[] args) {

	// create 3 BigInteger objects
	BigInteger bi1, bi2, bi3;

	bi1 = new BigInteger("4");

	// perform right shift operation on bi1 using 2 and -2
	bi2 = bi1.shiftRight(2);
	bi3 = bi1.shiftRight(-2);

	String str1 = "Right shift on " +bi1+ ", 2 times gives " +bi2;
	String str2 = "Right shift on " +bi1+ ", -2 times gives " +bi3;

	// print bi2, bi3 values
	System.out.println( str1 );
	System.out.println( str2 );

Let us compile and run the above program, this will produce the following result:

Right shift on 4, 2 times gives 1
Right shift on 4, -2 times gives 16