# Java.math.BigInteger.intValue() Method

## Description

The java.math.BigInteger.intValue() converts this BigInteger to an int. This conversion is analogous to a narrowing primitive conversion from long to int.

If this BigInteger is too big to fit in an int, only the low-order 32 bits are returned. This conversion can lose information about the overall magnitude of the BigInteger value as well as return a result with the opposite sign.

## Declaration

Following is the declaration for java.math.BigInteger.intValue() method.

```public int intValue()
```

## Specified by

intValue in class Number.

NA

## Return Value

This method returns this BigInteger converted to an int.

NA

## Example

The following example shows the usage of math.BigInteger.intValue() method.

```package com.tutorialspoint;

import java.math.*;

public class BigIntegerDemo {

public static void main(String[] args) {

// create 2 BigInteger objects
BigInteger bi1, bi2;

// create 2 Integer objects
Integer i1, i2;

// assign values to bi1, bi2
bi1 = new BigInteger("123");
bi2 = new BigInteger("9888486986");

// assign the integer values of bi1, bi2 to i1, i2
i1 = bi1.intValue();
i2 = bi2.intValue();

String str1 = "Integer value of " +bi1+ " is " +i1;
String str2 = "Integer value of " +bi2+ " is " +i2;

// print i1, i2 values
System.out.println( str1 );
System.out.println( str2 );
}
}
```

Let us compile and run the above program, this will produce the following result −

```Integer value of 123 is 123
Integer value of 9888486986 is 1298552394
```

java_math_biginteger.htm