Java.lang.System.exit() Method

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Description

The java.lang.System.exit() method terminates the currently running Java Virtual Machine.
The argument serves as a status code; by convention, a nonzero status code indicates abnormal termination.

Declaration

Following is the declaration for java.lang.System.exit() method

public static void exit(int status)

Parameters

  • status -- This is the exit status.

Return Value

This method does not return any value.

Exception

  • SecurityException -- if a security manager exists and its checkExit method doesn't allow exit with the specified status.

Example

The following example shows the usage of java.lang.System.exit() method.

package com.tutorialspoint;

import java.lang.*;

public class SystemDemo {

   public static void main(String[] args) {

      int arr1[] = { 0, 1, 2, 3, 4, 5 };
      int arr2[] = { 0, 10, 20, 30, 40, 50 };
      int i;
      
      // copies an array from the specified source array
      System.arraycopy(arr1, 0, arr2, 0, 1);
      System.out.print("array2 = ");
      System.out.print(arr2[0] + " ");
      System.out.print(arr2[1] + " ");
      System.out.println(arr2[2] + " ");
      
      for(i = 0;i < 3;i++) {
         if(arr2[i] > = 20) {
            System.out.println("exit...");
            System.exit(0);
         }
         else {
            System.out.println("arr2["+i+"] = " + arr2[i]);
         }
      }
   }
} 

Let us compile and run the above program, this will produce the following result:

array2 = 0 10 20
arr2[0] = 0
arr2[1] = 10
exit...



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