Java.lang.StrictMath.ulp() Method

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Description

The java.lang.StrictMath.ulp(double d) method returns the size of an ulp of the argument. An ulp of a double value is the positive distance between this floating-point value and the double value next larger in magnitude. For non-NaN x, ulp(-x) == ulp(x).It include these cases:

  • If the argument is NaN, then the result is NaN.
  • If the argument is positive or negative infinity, then the result is positive infinity.
  • If the argument is positive or negative zero, then the result is Double.MIN_VALUE.
  • If the argument is ±Double.MAX_VALUE, then the result is equal to 2971.

Declaration

Following is the declaration for java.lang.StrictMath.ulp() method

public static double ulp(double d)

Parameters

  • d -- This is the floating-point value whose ulp is to be returned.

Return Value

This method returns the size of an ulp of the argument.

Exception

  • NA

Example

The following example shows the usage of java.lang.StrictMath.ulp() method.

package com.tutorialspoint;

import java.lang.*;

public class StrictMathDemo {

  public static void main(String[] args) {
  
    double d1 = 5.5 , d2 = -2.9, d3 = 0.0;
  
    // returns the size of an ulp of the argument
    double ulpValue = StrictMath.ulp(d1); 
    System.out.println("Size of ulp of " + d1 + " = " + ulpValue);
    
    ulpValue = StrictMath.ulp(d2); 
    System.out.println("Size of ulp of " + d2 + " = " + ulpValue);
    
    ulpValue = StrictMath.ulp(d3); 
    System.out.println("Size of ulp of " + d3 + " = " + ulpValue);
 }
}

Let us compile and run the above program, this will produce the following result:

Size of ulp of 5.5 = 8.881784197001252E-16
Size of ulp of -2.9 = 4.440892098500626E-16
Size of ulp of 0.0 = 4.9E-324



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