Java.lang.StrictMath.sinh() Method


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Description

The java.lang.StrictMath.sinh() method returns the hyperbolic sine of a double value. The hyperbolic sine of x is defined to be (ex - e-x)/2 where e is Euler's number.It include these cases −

  • If the argument is NaN or an infinity, then the result is NaN.
  • If the argument is infinite, then the result is an infinity with the same sign as the argument.
  • If the argument is zero, then the result is a zero with the same sign as the argument.

Declaration

Following is the declaration for java.lang.StrictMath.sinh() method

public static double sinh(double x)

Parameters

x − This is the number whose hyperbolic sine is to be returned.

Return Value

This method returns the hyperbolic sine of x.

Exception

NA

Example

The following example shows the usage of java.lang.StrictMath.sinh() method.

package com.tutorialspoint;

import java.lang.*;

public class StrictMathDemo {

   public static void main(String[] args) {

      double d1 = (90*Math.PI)/180 , d2 = 50, d3 = 0;
   
      // returns the hyperbolic sine of a double value

      double sinhValue = StrictMath.sinh(d1); 
      System.out.println("Hyperbolic sine of d1 = " + sinhValue);

      sinhValue = StrictMath.sinh(d2); 
      System.out.println("Hyperbolic sine of d2 = " + sinhValue);

      sinhValue = StrictMath.sinh(d3); 
      System.out.println("Hyperbolic sine of d3 = " + sinhValue);
   }
}

Let us compile and run the above program, this will produce the following result −

Hyperbolic sin of d1 = 2.3012989023072947
Hyperbolic sin of d2 = 2.592352764293536E21
Hyperbolic sin of d3 = 0.0

java_lang_strictmath.htm

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