Java.lang.StrictMath.sin() Method

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Description

The java.lang.StrictMath.sin() method returns the trigonometric sine of an angle.It include these cases:

  • If the argument is NaN or an infinity, then the result is NaN.
  • If the argument is zero, then the result is a zero with the same sign as the argument.

Declaration

Following is the declaration for java.lang.StrictMath.sin() method

public static double sin(double a)

Parameters

  • a -- This is an angle, in radians.

Return Value

This method returns the sine of the argument.

Exception

  • NA

Example

The following example shows the usage of java.lang.StrictMath.sin() method.

package com.tutorialspoint;

import java.lang.*;

public class StrictMathDemo {

  public static void main(String[] args) {
  
    double d1 = (90*Math.PI)/180 , d2 = 0.0, d3 = (1.0/0.0) ;

    // returns the trigonometric sine of an angle 
    double sinValue = StrictMath.sin(d1); 
    System.out.println("Trigonometric sine of d1 = " + sinValue);
        
    sinValue = StrictMath.sin(d2); 
    System.out.println("Trigonometric sine of d2 = " + sinValue);
        
    sinValue = StrictMath.sin(d3); 
    System.out.println("Trigonometric sine of d3 = " + sinValue);
  }
}

Let us compile and run the above program, this will produce the following result:

Trigonometric sine of d1 = 1.0
Trigonometric sine of d2 = 0.0
Trigonometric sine of d3 = NaN



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