Java.lang.StrictMath.log() Method

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Description

The java.lang.StrictMath.log() method returns the natural logarithm (base e) of a double value.It include some cases:

  • If the argument is NaN or less than zero, then the result is NaN.
  • If the argument is positive infinity, then the result is positive infinity.
  • If the argument is positive zero or negative zero, then the result is negative infinity.

Declaration

Following is the declaration for java.lang.StrictMath.log() method

public static double log(double a)

Parameters

  • a -- This is the value.

Return Value

This method returns the value ln a i.e natural logarithm of a.

Exception

  • NA

Example

The following example shows the usage of java.lang.StrictMath.log() method.

package com.tutorialspoint;

import java.lang.*;

public class StrictMathDemo {

  public static void main(String[] args) {
  
    double d1 = 10 , d2 = 0.0 , d3 = (1.0/0.0), d4 = 1.0;

    // returns natural logarithm(base e) of a double  value
    double logValue = StrictMath.log(d1); 
    System.out.println("Log value of " + d1 + " = " + logValue);
        
    logValue = StrictMath.log(d2); 
    System.out.println("Log value of " + d2 + " = " + logValue);
        
    logValue = StrictMath.log(d3); 
    System.out.println("Log value of " + d3 + " = " + logValue);
        
    logValue = StrictMath.log(d4); 
    System.out.println("Log value of " + d4 + " = " + logValue);
  }
}

Let us compile and run the above program, this will produce the following result:

Log value of 10.0 = 2.302585092994046
Log value of 0.0 = -Infinity
Log value of Infinity = Infinity
Log value of 1.0 = 0.0



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