Java.lang.StrictMath.floor() Method

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Description

The java.lang.StrictMath.floor() method returns the largest (closest to positive infinity) double value that is less than or equal to the argument and is equal to a mathematical integer. It include some cases −

• If the argument value is already equal to a mathematical integer, then the result is the same as the argument.
• If the argument is NaN or an infinity or positive zero or negative zero, then the result is the same as the argument.

Declaration

Following is the declaration for java.lang.StrictMath.floor() method

public static double floor(double a)

Parameters

a − This is the value.

Return Value

This method returns the largest (closest to positive infinity) floating-point value that less than or equal to the argument and is equal to a mathematical integer.

Exception

NA

Example

The following example shows the usage of java.lang.StrictMath.floor() method.

package com.tutorialspoint;

import java.lang.*;

public class StrictMathDemo {

   public static void main(String[] args) {

      double d1 = 5.3 , d2 = 7.8, d3 = 1.5;

      // returns the largest double value, less than or equal to argument  
      double floorValue = StrictMath.floor(d1); 
      System.out.println("Floor value of " + d1 + " = " + floorValue);

      floorValue = StrictMath.floor(d2); 
      System.out.println("Floor value of " + d2 + " = " + floorValue);

      floorValue = StrictMath.floor(d3);
      System.out.println("Floor value of " + d3 + " = " + floorValue);
   }
}

Let us compile and run the above program, this will produce the following result −

Floor value of 5.3 = 5.0
Floor value of 7.8 = 7.0
Floor value of 1.5 = 1.0