# Java.lang.StrictMath.floor() Method

#### Complete Java Programming Fundamentals With Sample Projects

98 Lectures 7.5 hours

#### Get your Java dream job! Beginners interview preparation

85 Lectures 6 hours

#### Core Java bootcamp program with Hands on practice

Featured

99 Lectures 17 hours

## Description

The java.lang.StrictMath.floor() method returns the largest (closest to positive infinity) double value that is less than or equal to the argument and is equal to a mathematical integer. It include some cases −

• If the argument value is already equal to a mathematical integer, then the result is the same as the argument.
• If the argument is NaN or an infinity or positive zero or negative zero, then the result is the same as the argument.

## Declaration

Following is the declaration for java.lang.StrictMath.floor() method

```public static double floor(double a)
```

## Parameters

a − This is the value.

## Return Value

This method returns the largest (closest to positive infinity) floating-point value that less than or equal to the argument and is equal to a mathematical integer.

NA

## Example

The following example shows the usage of java.lang.StrictMath.floor() method.

```package com.tutorialspoint;

import java.lang.*;

public class StrictMathDemo {

public static void main(String[] args) {

double d1 = 5.3 , d2 = 7.8, d3 = 1.5;

// returns the largest double value, less than or equal to argument
double floorValue = StrictMath.floor(d1);
System.out.println("Floor value of " + d1 + " = " + floorValue);

floorValue = StrictMath.floor(d2);
System.out.println("Floor value of " + d2 + " = " + floorValue);

floorValue = StrictMath.floor(d3);
System.out.println("Floor value of " + d3 + " = " + floorValue);
}
}
```

Let us compile and run the above program, this will produce the following result −

```Floor value of 5.3 = 5.0
Floor value of 7.8 = 7.0
Floor value of 1.5 = 1.0
```
java_lang_strictmath.htm