Java.lang.StrictMath.exp() Method

Description

The java.lang.StrictMath.exp() method returns Euler's number e raised to the power of a double value.It include these cases:

• If the argument is NaN, then the result is NaN.
• If the argument is positive infinity, then the result is positive infinity.
• If the argument is negative infinity, then the result is positive zero.

Declaration

Following is the declaration for java.lang.StrictMath.exp() method

public static double exp(double a)

Parameters

• a -- This is the exponent to raise e to.

Return Value

This method returns the value e^a, where e is the base of the natural logarithms.

Exception

• NA

Example

The following example shows the usage of java.lang.StrictMath.exp() method.

package com.tutorialspoint;

import java.lang.*;

public class StrictMathDemo {

  public static void main(String[] args) {
  
    double d1 = 0.0 , d2 = -0.0, d3 = (1.0/0.0), d4 = 5;

    // returns Euler's number e raised to the power positive 0 
    double eulerValue = StrictMath.exp(d1); 
    System.out.println("Euler value of d1 = " + eulerValue);
        
    // returns Euler's number e raised to the power negative 0
    eulerValue = StrictMath.exp(d2); 
    System.out.println("Euler value of d2 = " + eulerValue);
        
    // returns Euler's number e raised to the power infinity
    eulerValue = StrictMath.exp(d3);
    System.out.println("Euler value of d3 = " + eulerValue);
        
    // returns Euler's number e raised to the power 5
    eulerValue = StrictMath.exp(d4);
    System.out.println("Euler value of d4 = " + eulerValue);
  }
}

Let us compile and run the above program, this will produce the following result:

Euler value of d1 = 1.0
Euler value of d2 = 1.0
Euler value of d3 = Infinity
Euler value of d4 = 148.4131591025766