Java.lang.StrictMath.ceil() Method

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Description

The java.lang.StrictMath.ceil() method returns the smallest (closest to negative infinity) double value that is greater than or equal to the argument and is equal to a mathematical integer.This include these cases −

• If the argument value is already equal to a mathematical integer, then the result is the same as the argument.
• If the argument is NaN or an infinity or positive zero or negative zero, then the result is the same as the argument.
• If the argument value is less than zero but greater than -1.0, then the result is negative zero.

Declaration

Following is the declaration for java.lang.StrictMath.ceil() method

public static double ceil(double a)

Parameters

a − This is the double value

Return Value

This method returns the smallest (closest to negative infinity) floating-point value that is greater than or equal to the argument and is equal to a mathematical integer.

Exception

NA

Example

The following example shows the usage of java.lang.StrictMath.ceil() method.

package com.tutorialspoint;

import java.lang.*;

public class StrictMathDemo {

   public static void main(String[] args) {

      double d1 = 5.3 , d2 = 7.8, d3 = 1.5;
   
      // returns the largest double value, greater than or equal to argument  
      double ceilValue = StrictMath.ceil(d1); 
      System.out.println("Ceil value of " + d1 + " = " + ceilValue);

      ceilValue = StrictMath.ceil(d2); 
      System.out.println("Ceil value of " + d2 + " = " + ceilValue);

      ceilValue = StrictMath.ceil(d3);
      System.out.println("Ceil value of " + d3 + " = " + ceilValue);
   }
}

Let us compile and run the above program, this will produce the following result −

Ceil value of 5.3 = 6.0
Ceil value of 7.8 = 8.0
Ceil value of 1.5 = 2.0