Java.lang.StrictMath.cbrt() Method

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Description

The java.lang.StrictMath.cbrt() method returns the cube root of a double value. For positive finite x, cbrt(-x) == -cbrt(x); that is, the cube root of a negative value is the negative of the cube root of that value's magnitude.This include these cases −

• If the argument is NaN, then the result is NaN.
• If the argument is infinite, then the result is an infinity with the same sign as the argument.
• If the argument is zero, then the result is a zero with the same sign as the argument.

Declaration

Following is the declaration for java.lang.StrictMath.cbrt() method

public static double cbrt(double a)

Parameters

a − This is the double value

Return Value

This method returns the cube root of a.

Exception

NA

Example

The following example shows the usage of java.lang.StrictMath.cbrt() method.

package com.tutorialspoint;

import java.lang.*;

public class StrictMathDemo {

   public static void main(String[] args) {

      double d1 = 8.05 , d2 = 729, d3 = 0;
   
      // returns the cube root of a double value
      double cbrtValue = StrictMath.cbrt(d1); 
      System.out.println("Cube root of " + d1 + " = " + cbrtValue);

      cbrtValue = StrictMath.cbrt(d2); 
      System.out.println("Cube root of " + d2 + " = " + cbrtValue);

      cbrtValue = StrictMath.cbrt(d3); 
      System.out.println("Cube root of " + d3 + " = " + cbrtValue);
   }
}

Let us compile and run the above program, this will produce the following result −

Cube root of 8.05 = 2.0041580161269152
Cube root of 729 = 9.0
Cube root of 0 = 0.0