Java.lang.StrictMath.cbrt() Method

Description

The java.lang.StrictMath.cbrt() method returns the cube root of a double value. For positive finite x, cbrt(-x) == -cbrt(x); that is, the cube root of a negative value is the negative of the cube root of that value's magnitude.This include these cases:

• If the argument is NaN, then the result is NaN.
• If the argument is infinite, then the result is an infinity with the same sign as the argument.
• If the argument is zero, then the result is a zero with the same sign as the argument.

Declaration

Following is the declaration for java.lang.StrictMath.cbrt() method

public static double cbrt(double a)

Parameters

• a -- This is the double value

Return Value

This method returns the cube root of a.

Exception

• NA

Example

The following example shows the usage of java.lang.StrictMath.cbrt() method.

package com.tutorialspoint;

import java.lang.*;

public class StrictMathDemo {

  public static void main(String[] args) {
  
    double d1 = 8.05 , d2 = 729, d3 = 0;

    // returns the cube root of a double value
    double cbrtValue = StrictMath.cbrt(d1); 
    System.out.println("Cube root of " + d1 + " = " + cbrtValue);
        
    cbrtValue = StrictMath.cbrt(d2); 
    System.out.println("Cube root of " + d2 + " = " + cbrtValue);
        
    cbrtValue = StrictMath.cbrt(d3); 
    System.out.println("Cube root of " + d3 + " = " + cbrtValue);
  }
}

Let us compile and run the above program, this will produce the following result:

Cube root of 8.05 = 2.0041580161269152
Cube root of 729 = 9.0
Cube root of 0 = 0.0