Java.lang.StrictMath.abs() Method

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Description

The java.lang.StrictMath.abs(float a) method returns the absolute value of a float value. If the argument is not negative, the argument is returned. If the argument is negative, the negation of the argument is returned. It includes some cases:

• If the argument is positive zero or negative zero, the result is positive zero.
• If the argument is infinite, the result is positive infinity.
• If the argument is NaN, the result is NaN.

Declaration

Following is the declaration for java.lang.StrictMath.abs() method

public static float abs(float a)

Parameters

a − This is the argument whose absolute value is to be determined.

Return Value

This method returns the absolute value of a float value.

Exception

NA

Example

The following example shows the usage of java.lang.StrictMath.abs() method.

package com.tutorialspoint;

import java.lang.*;

public class StrictMathDemo {

   public static void main(String[] args) {

      float f1 = 78 , f2 = -9;
     
      // returns the absolute value of positive float value
      float fAbsValue = StrictMath.abs(f1);
      System.out.println("absolute value of " + f1 + " = " + fAbsValue);
    
      // returns the absolute value of negative float value
      fAbsValue = StrictMath.abs(f2);
      System.out.println("absolute value of " + f2 + " = " + fAbsValue);
   }
}

Let us compile and run the above program, this will produce the following result −

absolute value of 78.0 = 78.0
absolute value of -9.0 = 9.0