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Java.lang.StrictMath.abs() Method
Description
The java.lang.StrictMath.abs(double a) method returns the absolute value of a double value. If the argument is not negative, the argument is returned. If the argument is negative, the negation of the argument is returned. It include some cases:
- If the argument is positive zero or negative zero, the result is positive zero.
- If the argument is infinite, the result is positive infinity.
- If the argument is NaN, the result is NaN.
Declaration
Following is the declaration for java.lang.StrictMath.abs() method
public static double abs(double a)
Parameters
a − This is the argument whose absolute value is to be determined.
Return Value
This method returns the absolute value of a double value.
Exception
NA
Example
The following example shows the usage of java.lang.StrictMath.abs() method.
package com.tutorialspoint; import java.lang.*; public class StrictMathDemo { public static void main(String[] args) { double d1 = 1245.9 , d2 = -987.8; // returns the absolute value of positive double value double dAbsValue = StrictMath.abs(d1); System.out.println("absolute value of " + d1 + " = " + dAbsValue); // returns the absolute value of negative double value dAbsValue = StrictMath.abs(d2); System.out.println("absolute value of " + d2 + " = " + dAbsValue); } }
Let us compile and run the above program, this will produce the following result −
absolute value of 1245.9 = 1245.9 absolute value of -987.8 = 987.8
java_lang_strictmath.htm
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