Java - Math floor(double) method

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Description

The Java Math floor(double a) returns the largest (closest to positive infinity) double value that is less than or equal to the argument and is equal to a mathematical integer. Special cases:

• If the argument value is already equal to a mathematical integer, then the result is the same as the argument.

• If the argument is NaN or an infinity or positive zero or negative zero, then the result is the same as the argument.

Declaration

Following is the declaration for java.lang.Math.floor() method

public static double floor(double a)

Parameters

a − a value.

Return Value

This method returns the largest (closest to positive infinity) floating-point value that less than or equal to the argument and is equal to a mathematical integer.

Exception

NA

Example 1

The following example shows the usage of Math floor() method.

package com.tutorialspoint;
public class MathDemo {
   public static void main(String[] args) {

      // get a double number
      double x = 10.7;

      // print the floor of the number
      System.out.println("Math.floor(" + x + ")=" + Math.floor(x));
   }
}

Output

Let us compile and run the above program, this will produce the following result −

Math.floor(10.7)=10.0

Example 2

The following example shows the usage of Math floor() method of zero value.

package com.tutorialspoint;
public class MathDemo {
   public static void main(String[] args) {

      // get a double number
      double x = 0.0;

      // print the floor of the number
      System.out.println("Math.floor(" + x + ")=" + Math.floor(x));
   }
}

Output

Let us compile and run the above program, this will produce the following result −

Math.floor(0.0)=0.0

Example 3

The following example shows the usage of Math floor() method of a negative number.

package com.tutorialspoint;
public class MathDemo {
   public static void main(String[] args) {

      // get a double number
      double x = -10.7;

      // print the floor of the number
      System.out.println("Math.floor(" + x + ")=" + Math.floor(x));
   }
}

Output

Let us compile and run the above program, this will produce the following result −

Math.floor(-10.7)=-11.0