Java.lang.Math.floor() Method

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Description

The java.lang.Math.floor(double a) returns the largest (closest to positive infinity) double value that is less than or equal to the argument and is equal to a mathematical integer. Special cases:

  • If the argument value is already equal to a mathematical integer, then the result is the same as the argument.

  • If the argument is NaN or an infinity or positive zero or negative zero, then the result is the same as the argument.

Declaration

Following is the declaration for java.lang.Math.floor() method

public static double floor(double a)

Parameters

  • a -- a value.

Return Value

This method returns the largest (closest to positive infinity) floating-point value that less than or equal to the argument and is equal to a mathematical integer.

Exception

  • NA

Example

The following example shows the usage of lang.Math.floor() method.

package com.tutorialspoint;

import java.lang.*;

public class MathDemo {

   public static void main(String[] args) {

      // get two double numbers
      double x = 60984.1;
      double y = -497.99;

      // call floor and print the result
      System.out.println("Math.floor(" + x + ")=" + Math.floor(x));
      System.out.println("Math.floor(" + y + ")=" + Math.floor(y));
      System.out.println("Math.floor(0)=" + Math.floor(0));


   }
}

Let us compile and run the above program, this will produce the following result:

Math.floor(60984.1)=60984.0
Math.floor(-497.99)=-498.0
Math.floor(0)=0.0



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