Java - Math exp(double) method

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Description

The Java Math exp(double a) returns Euler's number e raised to the power of a double value. Special cases:

• If the argument is NaN, the result is NaN.

• If the argument is positive infinity, then the result is positive infinity.

• If the argument is negative infinity, then the result is positive zero.

The computed result must be within 1 ulp of the exact result. Results must be semi-monotonic.

Declaration

Following is the declaration for java.lang.Math.exp() method

public static double exp(double a)

Parameters

a − the exponent to raise e to.

Return Value

This method returns the value e^a, where e is the base of the natural logarithms.

Exception

NA

Example 1

The following example shows the usage of Math exp() method.

package com.tutorialspoint;
public class MathDemo {
   public static void main(String[] args) {

      // get a double number
      double x = 0.5;
   
      // print e raised at x
      System.out.println("Math.exp(" + x + ")=" + Math.exp(x));
   }
}

Output

Let us compile and run the above program, this will produce the following result −

Math.exp(0.5)=1.6487212707001282

Example 2

The following example shows the another usage of Math exp() method with zero value.

package com.tutorialspoint;
public class MathDemo {
   public static void main(String[] args) {

      // get a double number
      double x = 0;
   
      // print e raised at x
      System.out.println("Math.exp(" + x + ")=" + Math.exp(x));
   }
}

Output

Let us compile and run the above program, this will produce the following result −

Math.exp(0.0)=1.0

Example 3

The following example shows the usage of Math exp() method with one value.

package com.tutorialspoint;
public class MathDemo {
   public static void main(String[] args) {

      // get a double number
      double x = 1;
   
      // print e raised at x
      System.out.println("Math.exp(" + x + ")=" + Math.exp(x));
   }
}

Output

Let us compile and run the above program, this will produce the following result −

Math.exp(1.0)=2.718281828459045