Java.lang.Math.cbrt() Method

Description

The java.lang.Math.cbrt(double a) returns the cube root of a double value. For positive finite x, cbrt(-x) == -cbrt(x); that is, the cube root of a negative value is the negative of the cube root of that value's magnitude. Special cases −

If the argument is NaN, then the result is NaN.
If the argument is infinite, then the result is an infinity with the same sign as the argument.
If the argument is zero, then the result is a zero with the same sign as the argument.

The computed result must be within 1 ulp of the exact result.

Declaration

Following is the declaration for java.lang.Math.cbrt() method

public static double cbrt(double a)

Parameters

a − a value.

Return Value

This method returns the cube root of a.

Exception

Example

The following example shows the usage of lang.Math.cbrt() method.

package com.tutorialspoint;

import java.lang.*;

public class MathDemo {

   public static void main(String[] args) {

      // get two double numbers
      double x = 125;
      double y = 10;

      // print the cube roots of three numbers
      System.out.println("Math.cbrt(" + x + ")=" + Math.cbrt(x));
      System.out.println("Math.cbrt(" + y + ")=" + Math.cbrt(y));
      System.out.println("Math.cbrt(-27)=" + Math.cbrt(-27));
   }
}

Let us compile and run the above program, this will produce the following result −

Math.cbrt(125)=5.0
Math.cbrt(10)=2.154434690031884
Math.cbrt(-27)=-3.0

java_lang_math.htm