Java.lang.Math.abs() Method


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Description

The java.lang.Math.abs(double a) returns the absolute value of a double value. If the argument is not negative, the argument is returned. If the argument is negative, the negation of the argument is returned.Special cases −

  • If the argument is positive zero or negative zero, the result is positive zero.
  • If the argument is infinite, the result is positive infinity.
  • If the argument is NaN, the result is NaN.

Declaration

Following is the declaration for java.lang.Math.abs() method

public static double abs(double a)

Parameters

a − the argument whose absolute value is to be determined

Return Value

This method returns the absolute value of the argument.

Exception

NA

Example

The following example shows the usage of lang.Math.abs() method.

package com.tutorialspoint;

import java.lang.Math;

public class MathDemo {

   public static void main(String[] args) {

      // get some doubles to find their absolute values
      double x = 4876.1874d;
      double y = -0.0d;
   
      // get and print their absolute values
      System.out.println("Math.abs(" + x + ")=" + Math.abs(x));
      System.out.println("Math.abs(" + y + ")=" + Math.abs(y));
      System.out.println("Math.abs(-9999.555d)=" + Math.abs(-9999.555d));
   }
}

Let us compile and run the above program, this will produce the following result −

Math.abs(4876.1874d)=4876.1874
Math.abs(-0.0d)=0.0
Math.abs(-9999.555d)=9999.555

java_lang_math.htm

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