Java.lang.Math.abs() Method

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Description

The java.lang.Math.abs(double a) returns the absolute value of a double value. If the argument is not negative, the argument is returned. If the argument is negative, the negation of the argument is returned.Special cases:

  • If the argument is positive zero or negative zero, the result is positive zero.
  • If the argument is infinite, the result is positive infinity.
  • If the argument is NaN, the result is NaN.

Declaration

Following is the declaration for java.lang.Math.abs() method

public static double abs(double a)

Parameters

  • a -- the argument whose absolute value is to be determined

Return Value

This method returns the absolute value of the argument.

Exception

  • NA

Example

The following example shows the usage of lang.Math.abs() method.

package com.tutorialspoint;

import java.lang.Math;

public class MathDemo {

   public static void main(String[] args) {

      // get some doubles to find their absolute values
      double x = 4876.1874d;
      double y = -0.0d;

      // get and print their absolute values
      System.out.println("Math.abs(" + x + ")=" + Math.abs(x));
      System.out.println("Math.abs(" + y + ")=" + Math.abs(y));
      System.out.println("Math.abs(-9999.555d)=" + Math.abs(-9999.555d));
   }
}

Let us compile and run the above program, this will produce the following result:

Math.abs(4876.1874d)=4876.1874
Math.abs(-0.0d)=0.0
Math.abs(-9999.555d)=9999.555



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