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Java - Long parseLong() method
Description
The Java Long parseLong(String s, int radix) parseLong(String s, int radix) method parses the string argument s as a signed long in the radix specified by the second argument radix.Some examples can be seen here −
parseLong("0", 10) returns 0L parseLong("11", 10) returns 111L parseLong("-0", 10) returns 0L parseLong("-BB", 16) returns -187L parseLong("1010110", 2) returns 86L parseLong("ADMIN", 27) returns 5586836L parseLong("99", 8) throws a NumberFormatException
Declaration
Following is the declaration for java.lang.Long.parseLong() method
public static long parseLong(String s, int radix) throws NumberFormatException
Parameters
s − This is a String containing the long representation to be parsed.
radix − This is the radix to be used while parsing s.
Return Value
This method returns the long represented by the string argument in the specified radix.
Exception
NumberFormatException − if the string does not contain a parsable long.
Example 1
The following example shows the usage of Long parseLong() method to parse a Long object from a string containing decimal number. We've created a String variable and assign it a string containing decimal number. Then using parseLong method, we're obtaining the Long object and printing it.
package com.tutorialspoint; public class LongDemo { public static void main(String[] args) { String str = "50"; /* returns an Long object holding the int value represented by string str */ System.out.println("Number = " + Long.parseLong(str, 10)); } }
Output
Let us compile and run the above program, this will produce the following result −
Number = 50
Example 2
The following example shows the usage of Long parseLong() method to get a Long object from a string containing a octal number. We've created a String variable and assign it a string containing an octal number. Then using parseLong method, we're obtaining the Long object and printing it.
package com.tutorialspoint; public class LongDemo { public static void main(String[] args) { String str = "50"; /* returns an Long object holding the octal int value represented by string str */ System.out.println("Number = " + Long.parseLong(str,8)); } }
Output
Let us compile and run the above program, this will produce the following result −
Number = 40
Example 3
The following example shows the usage of Long parseLong() method to get a Long object from a string containing a hexadecimal number. We've created a String variable and assign it a string containing an hexadecimal number. Then using parseLong method, we're obtaining an Long object and printed.
package com.tutorialspoint; public class LongDemo { public static void main(String[] args) { String str = "50"; /* returns an Long object holding the hexadecimal int value represented by string str */ System.out.println("Number = " + Long.parseLong(str,16)); } }
Output
Let us compile and run the above program, this will produce the following result −
Number = 80