Java.lang.Long.compareTo() Method

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Description

The java.lang.Long.compareTo() method compares two Long objects numerically.

Declaration

Following is the declaration for java.lang.Long.compareTo() method

public int compareTo(Long anotherLong)

Parameters

  • anotherLong -- This is the Long to be compared.

Return Value

This method returns the value 0 if this Long is equal to the argument Long, value less than 0 if this Long is numerically less than the argument Long and a value greater than 0 if this Long is numerically greater than the argument Long (signed comparison).

Exception

  • NA

Example

The following example shows the usage of java.lang.Long.compareTo() method.

package com.tutorialspoint;

import java.lang.*;

public class LongDemo {

   public static void main(String[] args) {

     // compares two Long objects numerically
     Long obj1 = new Long(63255);
     Long obj2 = new Long(71678);
     int retval =  obj1.compareTo(obj2);
    
     if(retval > 0) {
        System.out.println("obj1 is greater than obj2");
     }
     else if(retval < 0) {
        System.out.println("obj1 is less than obj2");
     }
     else {
        System.out.println("obj1 is equal to obj2");
     }
   }
}

Let us compile and run the above program, this will produce the following result:

obj1 is less than obj2



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