Java.lang.Integer.reverseBytes() Method

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Description

The java.lang.Integer.reverseBytes() method returns the value obtained by reversing the order of the bytes in the two's complement representation of the specified int value.

Declaration

Following is the declaration for java.lang.Integer.reverseBytes() method

public static int reverseBytes(int i)

Parameters

  • i -- This is the int value.

Return Value

This method returns the value obtained by reversing the bytes in the specified int value.

Exception

  • NA

Example

The following example shows the usage of java.lang.Integer.reverseBytes() method.

package com.tutorialspoint;

import java.lang.*;

public class IntegerDemo {

   public static void main(String[] args) {

     int i = 170;
     System.out.println("Number = " + i);
    
     /* returns the string representation of the unsigned integer value 
     represented by the argument in binary (base 2) */
     System.out.println("Binary = " + Integer.toBinaryString(i));

     // returns the number of one-bits 
     System.out.println("Number of one bits = " + Integer.bitCount(i)); 
  
     /* returns the value obtained by reversing the bytes in the 
     specified int value */ 
     System.out.println("After reversing = " + Integer.reverseBytes(i));
   }
} 

Let us compile and run the above program, this will produce the following result:

Number = 170
Binary = 10101010
Number of one bits = 4
After reversing = -1442840576



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