Java.lang.Integer.parseInt() Method

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Description

The java.lang.Integer.parseInt(String s) method parses the string argument s as a signed decimal integer.

Declaration

Following is the declaration for java.lang.Integer.parseInt() method

public static int parseInt(String s) throws NumberFormatException

Parameters

  • s -- This is a String containing the int representation to be parsed.

Return Value

This method returns the integer value represented by the argument in decimal.

Exception

  • NumberFormatException -- if the string does not contain a parsable integer.

Example

The following example shows the usage of java.lang.Integer.parseInt() method.

package com.tutorialspoint;

import java.lang.*;

public class IntegerDemo {

   public static void main(String[] args) {

     // parses the string argument
     int a = Integer.parseInt("12");
     int b = Integer.parseInt("26");
     int c = Integer.parseInt("54");

     int m = a * b * c;
     System.out.print("Value after multiplying = " + m);
   }
} 

Let us compile and run the above program, this will produce the following result:

Value after multiplying = 16848



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