Java.lang.Integer.highestOneBit() Method

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Description

The java.lang.Integer.highestOneBit() method returns an int value with at most a single one-bit, in the position of the highest-order ("leftmost") one-bit in the specified int value. It returns zero if the specified value has no one-bits in its two's complement binary representation, that is, if it is equal to zero.

Declaration

Following is the declaration for java.lang.Integer.highestOneBit() method

public static int highestOneBit(int i)

Parameters

  • i -- This is the int value.

Return Value

This method returns an int value with a single one-bit, in the position of the highest-order one-bit in the specified value, or zero if the specified value is itself equal to zero.

Exception

  • NA

Example

The following example shows the usage of java.lang.Integer.highestOneBit() method.

package com.tutorialspoint;

import java.lang.*;

public class IntegerDemo {

   public static void main(String[] args) {

     int i = 170;
     System.out.println("Number = " + i);
    
     /* returns the string representation of the unsigned integer value 
     represented by the argument in binary (base 2) */
     System.out.println("Binary = " + Integer.toBinaryString(i));

     // returns the number of one-bits 
     System.out.println("Number of one bits = " + Integer.bitCount(i));

     /* returns an int value with at most a single one-bit, in the position 
     of the highest-order ("leftmost") one-bit in the specified int value */ 
     System.out.println("Highest one bit = " + Integer.highestOneBit(i));
   }
}

Let us compile and run the above program, this will produce the following result:

Number = 170
Binary = 10101010
Number of one bits = 4
Highest one bit = 128



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