Java.lang.Double.longBitsToDouble() Method
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Description
The java.lang.Double.longBitsToDouble() method returns the double value corresponding to a given bit representation. The argument is considered to be a representation of a floating-point value according to the IEEE 754 floating-point "double format" bit layout.It includes the following important points:
- If the argument is 0x7ff0000000000000L, the result is positive infinity.
- If the argument is 0xfff0000000000000L, the result is negative infinity.
Declaration
Following is the declaration for java.lang.Double.longBitsToDouble() method
public static double longBitsToDouble(long bits)
Parameters
bits -- This is any long integer.
Return Value
This method returns the double floating-point value with the same bit pattern.
Exception
NA
Example
The following example shows the usage of java.lang.Double.longBitsToDouble() method.
package com.tutorialspoint;
import java.lang.*;
public class DoubleDemo {
public static void main(String[] args) {
Double d = new Double("15.30");
/* returns the double value corresponding to a given bit
representation */
System.out.println(d.longBitsToDouble(6757689));
System.out.println(d.longBitsToDouble(0x7ff0000000000000L));
System.out.println(d.longBitsToDouble(0xfff0000000000000L));
}
}
Let us compile and run the above program, this will produce the following result:
3.338742E-317 Infinity -Infinity