Java.lang.Byte.compareTo() Method

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Description

The java.lang.Byte.compareTo(Byte anotherByte) compares two Byte objects numerically.

Declaration

Following is the declaration for java.lang.Byte.compareTo() method

public int compareTo(Byte anotherByte)

Specified by

compareTo in interface Comparable<Byte>

Parameters

  • anotherByte - the Byte to be compared

Return Value

This method returns the value 0 if this Byte is equal to the argument Byte; a value less than 0 if this Byte is numerically less than the argument Byte; and a value greater than 0 if this Byte is numerically greater than the argument Byte (signed comparison).

Exception

  • NA

Example

The following example shows the usage of lang.Byte.compareTo() method.

package com.tutorialspoint;

import java.lang.*;

public class ByteDemo {

   public static void main(String[] args) {

       // create 2 Byte objects b1, b2
      Byte b1, b2;

      // assign values to b1, b2
      b1 = new Byte("-100");
      b2 = new Byte("10");

      // create an int res
      int res;

      // compare b1 with b2 and assign result to res
      res = b1.compareTo(b2);

      String str1 = "Both values are equal ";
      String str2 = "First value is greater";
      String str3 = "Second value is greater";

      if( res == 0 ){
      	 System.out.println( str1 );
      }
      else if( res > 0 ){
      	 System.out.println( str2 );
      }
      else if( res < 0 ){
      	 System.out.println( str3 );
      }
   }
}

Let us compile and run the above program, this will produce the following result:

Second value is greater



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