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Java.io.RandomAccessFile.writeInt() Method
Description
The java.io.RandomAccessFile.writeInt(int v) method writes an int to the file as four bytes, high byte first. The write starts at the current position of the file pointer.
Declaration
Following is the declaration for java.io.RandomAccessFile.writeInt() method.
public final void writeInt(int v)
Parameters
v − a int value to be written.
Return Value
This method does not return a value.
Exception
IOException − If an I/O error occurs.
Example
The following example shows the usage of java.io.RandomAccessFile.writeInt() method.
package com.tutorialspoint; import java.io.*; public class RandomAccessFileDemo { public static void main(String[] args) { try { int f = 1847; // create a new RandomAccessFile with filename test RandomAccessFile raf = new RandomAccessFile("c:/test.txt", "rw"); // write an int in the file raf.writeInt(f); // set the file pointer at 0 position raf.seek(0); // read int System.out.println("" + raf.readInt()); // set the file pointer at 0 position raf.seek(0); // write a int at the start raf.writeInt(200); // set the file pointer at 0 position raf.seek(0); // read int System.out.println("" + raf.readInt()); } catch (IOException ex) { ex.printStackTrace(); } } }
Assuming we have a text file c:/test.txt, which has the following content. This file will be used as an input for our example program −
ABCDE
Let us compile and run the above program, this will produce the following result −
1847 200
java_io_randomaccessfile.htm
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