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- Java.io package Useful Resources
- Java.io - Discussion
Java.io.RandomAccessFile.writeFloat() Method
Description
The java.io.RandomAccessFile.writeFloat(float v) method converts the float argument to an int using the floatToIntBits method in class Float, and then writes that int value to the file as a four-byte quantity, high byte first. The write starts at the current position of the file pointer.
Declaration
Following is the declaration for java.io.RandomAccessFile.writeFloat() method.
public final void writeFloat(float v)
Parameters
v − a float value to be written.
Return Value
This method does not return a value.
Exception
IOException − If an I/O error occurs.
Example
The following example shows the usage of java.io.RandomAccessFile.writeFloat() method.
package com.tutorialspoint; import java.io.*; public class RandomAccessFileDemo { public static void main(String[] args) { try { float f = 1847.4986f; // create a new RandomAccessFile with filename test RandomAccessFile raf = new RandomAccessFile("c:/test.txt", "rw"); // write a float in the file raf.writeFloat(f); // set the file pointer at 0 position raf.seek(0); // read float System.out.println("" + raf.readFloat()); // set the file pointer at 0 position raf.seek(0); // write a float at the start raf.writeFloat(473.5645f); // set the file pointer at 0 position raf.seek(0); // read float System.out.println("" + raf.readFloat()); } catch (IOException ex) { ex.printStackTrace(); } } }
Assuming we have a text file c:/test.txt, which has the following content. This file will be used as an input for our example program −
ABCDE
Let us compile and run the above program, this will produce the following result −
1847.4987 473.5645