Java.io.RandomAccessFile.writeByte() Method

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Description

The java.io.RandomAccessFile.writeByte(int v) method writes a byte to the file as a one-byte value. The write starts at the current position of the file pointer.

Declaration

Following is the declaration for java.io.RandomAccessFile.writeByte() method

public final void writeByte(int v)

Parameters

  • v -- a byte value to be written.

Return Value

This method does not return a value.

Exception

  • IOException -- if an I/O error occurs.

Example

The following example shows the usage of java.io.RandomAccessFile.writeByte() method.

package com.tutorialspoint;

import java.io.*;

public class RandomAccessFileDemo {

   public static void main(String[] args) {
      try {
         byte[] b1 = {15, 8};
         // create a new RandomAccessFile with filename test
         RandomAccessFile raf = new RandomAccessFile("c:/test.txt", "rw");

         // write something in the file
         raf.writeByte(b1[0]);

         // set the file pointer at 0 position
         raf.seek(0);

         // read byte
         System.out.println("" + raf.readByte());

         // set the file pointer at 0 position
         raf.seek(0);

         // write 0 at the start
         raf.writeByte(b1[1]);

         // set the file pointer at 0 position
         raf.seek(0);

         // read byte
         System.out.println("" + raf.readByte());
      } catch (IOException ex) {
         ex.printStackTrace();
      }

   }
}

Assuming we have a text file c:/test.txt, which has the following content. This file will be used as an input for our example program:

ABCDE  

Let us compile and run the above program, this will produce the following result:

15
8



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