Java.io.RandomAccessFile.readByte() Method

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Description

The java.io.RandomAccessFile.readByte() method reads a signed eight-bit value from this file. This method reads a byte from the file, starting from the current file pointer.

Declaration

Following is the declaration for java.io.RandomAccessFile.readByte() method.

public final byte readByte()

Parameters

NA

Return Value

This method returns the next byte of this file as a signed eight-bit byte.

Exception

• IOException − If an I/O error occurs.Not thrown if end-of-file has been reached.

• EOFException − If this file has reached the end

Example

The following example shows the usage of java.io.RandomAccessFile.readByte() method.

package com.tutorialspoint;

import java.io.*;

public class RandomAccessFileDemo {
   public static void main(String[] args) {
   
      try {
         // create a new RandomAccessFile with filename test
         RandomAccessFile raf = new RandomAccessFile("c:/test.txt", "rw");

         // write something in the file
         raf.writeUTF("Hello World");

         // set the file pointer at 0 position
         raf.seek(0);

         // read byte
         System.out.println("" + raf.readByte());

         // set the file pointer at 0 position
         raf.seek(0);

         // write 0 at the start
         raf.write(0);

         // read byte
         System.out.println("" + raf.readByte());
      } catch (IOException ex) {
         ex.printStackTrace();
      }
   }
}

Assuming we have a text file c:/test.txt, which has the following content. This file will be used as an input for our example program −

ABCDE  

Let us compile and run the above program, this will produce the following result −

0
11