Java.io.DataOutputStream.writeByte() Method

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Description

The java.io.BufferedInputStream.writeByte(int v) method writes a byte to the underlying stream as a 1-byte value. The counter is incremented by 1 on successful execution of this method.

Declaration

Following is the declaration for java.io.DataOutputStream.writeByte(int v) method:

public final void writeByte(int v)

Parameters

  • v -- A byte value to be written to the stream.

Return Value

This method does not return any value.

Exception

  • IOException -- If an I/O error occurs.

Example

The following example shows the usage of java.io.DataOutputStream.writeByte(int v) method.

package com.tutorialspoint;

import java.io.ByteArrayOutputStream;
import java.io.DataOutputStream;
import java.io.IOException;

public class DataOutputStreamDemo {
   public static void main(String[] args) throws IOException {
      
      ByteArrayOutputStream baos = null;
      DataOutputStream dos = null;
      byte[] buf = {12, 15, 30, 40, 5, 7};
      
      try{
         // create byte array output stream
         baos = new ByteArrayOutputStream();
         
         // create data output stream
         dos = new DataOutputStream(baos);
         
         // write to the output stream from the buffer
         for(byte b: buf)
         {
            dos.writeByte(b);
         }
         // flushes bytes to underlying output stream
         dos.flush();
   
         // for each byte in the buffer content
         for(byte b:baos.toByteArray())
         {   
            // print character
            System.out.print(b + " ");
         }
      }catch(Exception e){
         // if any error occurs
         e.printStackTrace();
      }finally{
         
         // releases all system resources from the streams
         if(baos!=null)
            baos.close();
         if(dos!=null)
            dos.close();
      }
   }
}

Let us compile and run the above program, this will produce the following result:

12 15 30 40 5 7 



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