Java Examples - Multiple Exceptions (Array out of bound)

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Problem Description:

How to handle multiple exceptions while array is out of bound?

Solution:

This example shows how to handle multiple exception methods by using System.err.println() method of System class .

public class Main {
   public static void main (String args[]) {
      int array[]={20,20,40};
      int num1=15,num2=10;
      int result=10;
      try {
         result = num1/num2;
         System.out.println("The result is" +result);
         for(int i =5;i >=0; i--) {
            System.out.println
            ("The value of array is" +array[i]);
         }
      }
      catch (ArrayIndexOutOfBoundsException e) {
         System.out.println("Array is out of Bounds"+e);
      }
      catch (ArithmeticException e) {
         System.out.println ("Can't divide by Zero"+e);
      }
   }
}

Result:

The above code sample will produce the following result.

The result is1
Array is out of Boundsjava.lang.ArrayIndexOutOfBoundsException
: 5


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